InterviewSolution
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InterviewSolution
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`int(sin(x-alpha))/(sin(x+alpha))dx` का मान ज्ञात कीजिए। |
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Answer» माना `I = int(sin(x -alpha))/(sin(x+alpha))dx` माना ` x + alpha = t " "rArr x = t - alpha rArr dx = dt` `therefore" "I int (sin(x-alpha))/(sin t)dt` ` = int [(sin t cos 2alpha)/(sin t) - (cos t sin 2alpha)/(sin t)]dt ` ` = int cos 2alpha dt - int sin2alpha cot t dt` `=cos2alpha int dt - sin 2alpha int cot t dt ` `= t cos 2alpha - sn 2 alpha log|sin t|+c` `=(x+alpha) cos2alpha - sin 2 alpha log|sin (x +alpha)|+c` `= x cos 2 alpha - sin 2 alpha log|sin (x + alpha )|+c_(1)` जहाँ` c_(1) = c + alpha cos 2alpha` |
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