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`int(sinx)/((1+cos x)(2+3 cos x))` का मान ज्ञात कीजिए ।

Answer» माना `cos x = t rArr" "-sin x dx =dt`
`therefore" "int(sinx)/((1+cos x)(2+3cosx))dx=-int(dt)/((1+t)(2+3t))`
`=-int[(-1)/((1+t))+(3)/((2+3t))]dt`
`=int(1)/((1+t))dt-3int(1)/((2+3t))dt`
`=log (1+t)-3.(1)/(3)log(2+3t)+c`
`=log((1+t))/((2+3t))+c=log ((1+cos x)/(2+3 cos x))+c`


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