InterviewSolution
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`int(sinx)/((1+cos x)(2+3 cos x))` का मान ज्ञात कीजिए । |
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Answer» माना `cos x = t rArr" "-sin x dx =dt` `therefore" "int(sinx)/((1+cos x)(2+3cosx))dx=-int(dt)/((1+t)(2+3t))` `=-int[(-1)/((1+t))+(3)/((2+3t))]dt` `=int(1)/((1+t))dt-3int(1)/((2+3t))dt` `=log (1+t)-3.(1)/(3)log(2+3t)+c` `=log((1+t))/((2+3t))+c=log ((1+cos x)/(2+3 cos x))+c` |
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