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`inte^(x)(1-cotx+cot^(2)x)dx=`A. `e^(x)cotx+C`B. `-e^(x)cotx+C`C. `e^(x)"cosec "x+C`D. `-e^(x)"cosec " x+C` |
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Answer» Correct Answer - b We have , `I=inte^(x)(1-cotx+cot^(2)x)dx=inte^(x)(1+cot^(2)x-cotx)dx` `rArr I=inte^(x)(-cotx + " cosec "^(2)x)dx=-e^(x)cotx+C` |
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