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Integrate ∫ log⁡x^2 dx(a) log⁡x^2 + x+C(b) x log⁡x^2 – 2x+C(c) x log⁡x^2 – 1+C(d) x log⁡x^2 + x+CThis question was addressed to me in homework.This intriguing question comes from Integration by Parts topic in chapter Integrals of Mathematics – Class 12

Answer» RIGHT answer is (b) X log⁡x^2 – 2X+C

The best I can explain: By using ∫ U.v DX=u∫ v dx-∫ u'(∫ v dx)

∫ log⁡x^2.1 dx=log⁡x^2 ∫ dx-\(\int \frac{1}{x^2}.2x \int dx\)

=x log⁡x^2 – 2∫ 1/x.x dx

=x log⁡x^2 – 2∫ dx

=x log⁡x^2 – 2x+C


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