InterviewSolution
Saved Bookmarks
| 1. |
Integrate ∫ logx^2 dx(a) logx^2 + x+C(b) x logx^2 – 2x+C(c) x logx^2 – 1+C(d) x logx^2 + x+CThis question was addressed to me in homework.This intriguing question comes from Integration by Parts topic in chapter Integrals of Mathematics – Class 12 |
|
Answer» RIGHT answer is (b) X logx^2 – 2X+C The best I can explain: By using ∫ U.v DX=u∫ v dx-∫ u'(∫ v dx) ∫ logx^2.1 dx=logx^2 ∫ dx-\(\int \frac{1}{x^2}.2x \int dx\) =x logx^2 – 2∫ 1/x.x dx =x logx^2 – 2∫ dx =x logx^2 – 2x+C |
|