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Integrating factor of the differential equation `(x+1)(dy)/(dx)-y=e^(3x)(x+1)^(2)`, isA. `-(x+1)`B. `log(x+1)`C. `e^(x+1)`D. `(1)/(x+1)` |
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Answer» Correct Answer - D We have, `(dy)/(dx)-(1)/(x+1)y=e^(3x)(x+1)` `therefore" I.F."=e^(-int(1)/(x+1)dx)=e^(-log(x+1))=(1)/(x+1)` |
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