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Intensity at A due to source is I. Without concave mirror, then find out the intensity of A after placing concave mirror. |
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Answer» Solution :`P=Ixx4pi (10)^(2)` Intensity at `P=P/("Area")` `=P/(4pi (30)^(2))=I/9` Now `R/60=x/20` `x=r/3` Power INCIDENT on mirror `P_(p)=I/9xx PI R^(2)` This power will be incident on `pix^(2)` area So Intensity from mirror `=(Ixxpi R^(2))/(9pi (R//3)^(2))=I` So TOTAL, `I = I + I = 2I` |
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