1.

Intensity of point-like source at 1000 m is I. it is changed to 16I, then required distand will be

Answer»

250 m
500 m
750 m
800 m

Solution :RELATION of intensity at distance r from POINT like source,
`I=(phi)/(4 PI r^2)`
`therefore I prop (1)/(r^2)`
`therefore (I)/(I.)=((r.)/(r))^2`
`therefore (I)/(16 I)=(r.^2)/((1000 m)^2)`
`therefore r.^2=((1000 m)^2)/(16)`
`therefore r.=(1000m)/(4)`
`therefore r.=250` m


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