1.

Internal Energy (E,also denoted by U): Every system having some quantity of matter is associated with a definite amount of energy, called internal energy. E=E_("Transiational")+E_("Rotational")+E_("Vibrational")+E_("bonding")+.... DeltaE=E_("Final")-E_("initial") DeltaE=q_v, heat supplied to a gas at constant volume, since all the heat supplied goes to increase the internal energy to the gas. It is an extensive property & a state function.It is exclusively a function of temperature. If DeltaT=0 , DeltaE=0 as well. The internal energy of a certain substance is given by the following equation : U=3 PV+84 where U is given in kJ/kg, P is in kPa, and V is in m^3//kg A system composed of 3 kg of this substance expands from an initial pressure of 400 kPa and a volume of A 0.2 m^3 to a final pressure 100 kPa in a process in which pressure and volume are related by PV^2=constant. In another process the same system expands according to the same pressure-volume relationship as in above question, but from the same initial state of the final state as in above question, but the heat transfer in this case is +30 kJ.Then the work transfer for this process is :

Answer»

`-80 kJ`
`-60 kJ`
`-90 kJ`
`-150 kJ`

Solution :SINCE the end states are the same, `DELTAU` would remain the same as in above PROBLEM.
`W=DeltaU-q`
`W= -120-30= -150 kJ`


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