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Internal resistance of cell having emf 24 V is 0.12 Omega. If cell is joined with external resistance 3 Omega, so terminal voltage of cell is .......

Answer»

23.08 V
2V
0.1 V
3.8 V

Solution :23.08 V
In `EPSILON = V + IR`
I = `(epsilon)/(R + r) = (24)/(3.0 + 0.12) = (24)/(3.12) = 7.6 `A
V = `epsilon - Ir`
=` 24 - 7.6 XX .12`
= 24 - 0.912
23.08 V


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