`intsin^(2)x cos^(2) xdx = (1)/(8)[x - (sin 4x)/(4)]+c` सिद्ध कीजिये -

`intsin^(2)x cos^(2) xdx = (1)/(8)[x - (sin 4x)/(4)]+c` सिद्�

1.	`intsin^(2)x cos^(2) xdx = (1)/(8)[x - (sin 4x)/(4)]+c` सिद्ध कीजिये -
Answer» बाया पक्ष `=intsin^(2)x cos^(2)x dx` ` = int(sinx cos x)^(2)dx = (1)/(4)(2sin x cos x)^(2)dx` `=int(1)/(4)(sin 2x)^(2)dx = int(1)/(4)[(1-cos 4x)/(2)]dx` `= (1)/(8)(1-cos 4x)dx`