1.

inXI0number of molestheocalerelate11 gm of coz7) 11.2 e of coz3:01131023 malecules of soi) 25gm of Na32 gm of So2

Answer»

Given mass w= 11g

Molar mass of CO2= 12+2×16=44Now no of mole =w/m= 11/44

=1/4

= 0.25 mole Ans

w =11 g so molar of co2 12+2×6=44then 1 g Mai 11/44=0.25



Discussion

No Comment Found