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Iodobenzene( C_(6)H_(5)I) is prepared from aniline (C_(6)H_(5)NH_(2)) in a two step process as shown below C_(6)H_(5)NH_(2) + HNO_(3) + HCl to C_(6)H_(5)N_(2)""^(+)Cl^(-) +2H_(2)O C_(6)H_(5)N_(2) ^(+)Cl^(-) + Kl to C_(6)H_(5)I + N_(2) + KCl In an actual preparation 9.30 g of analine was converted to 16.32 g of iodobenzene . The percentage yeild of iodobenzene is : (I = 127 ) |
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