1.

Ionic conductance at infinite dilution of Al^(3+) and SO_(4)^(2-) are 189 and 160 mho cm^(2) "equiv"^(-1). Calculate the equivalent and molar conductance of the electrolyte Al_2(SO_4)_3 at infinite dilution.

Answer»

Solution :(i) MOLAR conductance, `(Lambda_m^@)_(Al_2(SO_4)_3) = 2(Lambda_m^@)_(AL^(3+)) + 3(Lambda_m^@)_(SO_4^(2-))`
`=(2 xx 189) + (3 xx 160)`
`= 378 + 480`
`= 858` MHO `cm^(2) MOL^(-1)`.
(ii) Equivalent conductance `(Lambda_(oo))_(Al_2(SO_4)_(3)) = 1/3 (lambda_(oo))_(Al^(3+)) + 1/2(lambda_(oo))_(SO_4^(2-))`
`= 189/3 + 160/2`
`= 63 + 80`
`143` mho `cm^2 (g"equiv")^(-1)`.


Discussion

No Comment Found

Related InterviewSolutions