1.

Ionisation energy and electron affinity of fluorine are respectively 17.42 and 3.45 eV. Calculate electronegativity of fluorine atom.

Answer»


Solution :ACCORDING to Mulliken's electronegativity `(chi_(M)) = ("IONISATION energy +ELECTRON affinity")/(2)`
`= (17.42 +3.45)/(2) = 10.435`
THEREFORE, electronegativity on Pauling's SCALE `(chi_(P)) = (10.435)/(2.8) = 3.726`


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