1.

Ionisation energy of He^(+) is 19.6xx10^(-18)J"atom"^(-1). The energy of first stationary state (n=1) of Li^(2+) is

Answer»

`-2.2xx10^(-15)"atom"^(-1)`
`8.82xx10^(-178)J"atom"(-1)`
`4.41xx10^(-16)J"atom"^(-1)`
`-4.41xx10^(-17)J"atom"^(-1)`

Solution :IE of`He^(+)`ion= IE of Hatom`xxZ^(2)` `19.6xx10^(-18)J"atom"^(-1)=4XX` I.E. of H atom
`:.`I.E of Hatom `=(19.6xx10^(-18))/4`
`=4.9xx10^(-18)J"atom"^(-1)`
I.E of `LI^(2-)` ion = I.E. of H atom `xx(3)^(2)`


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