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Ionisation paotential and electron affinity of fluorine are `17.42` and `3.45eV` respectively .Calculate the electronegativity of fluorine on Mulliken scale and Pauling scale . |
Answer» According to Mulliken equation , ` X =(IP +EA)/(2)` , When both `IP` and `EA` are taken in `eV`. `(X_F)_M = (17.42 +3.45)/(2) =10.435` `(X_F)_P= (10.435)/(2.8) =3.726 [or (Z_F)_P =(IP+EA)/(5.6)]` |
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