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Ionisation potential of hydrogen in kJ mol-1 unit is1312.0. What will be its value in unit of eV atom-l[IeV 1.6 x 10-19J1 2 |
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Answer» eV = electronvolt kJ =kilojoule 1eV= 1.6021765×10⁻²²kJ We first convert kJ to Ev eV = 1312/(1.6021765×10⁻²²) = 8.18886 x 10^24 Then we convert to Ev/Atom by dividing byAvogadro’s number eV/Atom = (8.18886 x 10^24)/6.022x10^23) = 13.6 |
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