1.

Ir ABCD is a cyclic quadrilateral, then presinA + sinB = sin C + sin D​

Answer»

ANSWER:

In a cyclic QUADRILATERAL, sum of OPPOSITE ANGLES is 180.

So, A+C=180⇒C=180−A⇒sinC=sin(180−A)=sinA

B+D=180⇒D=180−B⇒sinD=sin(180−B)=sinB

So,

sinA+sinB−sinC−sinD

=sinA+sinB−sinA−sinB

=0


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