Iron forms iron halides salts by reacting the metal directly with halogen. FeI_(3) does not exist. FeF_(3) is white soled inspite of five unpaired electronswith d^(5) configuration . FeCl_(3) is soluble in water and is used as a mordant in dyeing industry. Q.FeCl_(3) solution added to K_(4)[Fe(CN)_(6)] gives A while with KSCN gives B. A and B respectively are:

Iron forms iron halides salts by reacting the metal directly with halo

1.	Iron forms iron halides salts by reacting the metal directly with halogen. FeI_(3) does not exist. FeF_(3) is white soled inspite of five unpaired electronswith d^(5) configuration . FeCl_(3) is soluble in water and is used as a mordant in dyeing industry. Q.FeCl_(3) solution added to K_(4)[Fe(CN)_(6)] gives A while with KSCN gives B. A and B respectively are:
Answer» `Fe_(3)[Fe(CN)_(6)]_(2), Fe(CNS)_(3)` `Fe_(4)[Fe(CN)_(6)]_(2), KFE(CNS)_(3)` `Fe_(4)[Fe(CN)_(6)]_(3), K_(3)[Fe(CNS)_(6)]` `Fe_(4)[Fe(CN)_(6)]_(3), K_(3)[Fe(SCN)_(6)]` Answer :D