Iron is corroding at a current density of 1.69*10^-4 amp/cm^2. What would be the corrosion rate in MPY?(a) 423(b) 77(c) 473(d) 97This question was addressed to me in an internship interview.This is a very interesting question from Corrosion Rate Expression topic in portion Corrosion Principles of Corrosion Engineering

Iron is corroding at a current density of 1.69*10^-4 amp/cm^2. What wo

1.	Iron is corroding at a current density of 1.69*10^-4 amp/cm^2. What would be the corrosion rate in MPY?(a) 423(b) 77(c) 473(d) 97This question was addressed to me in an internship interview.This is a very interesting question from Corrosion Rate Expression topic in portion Corrosion Principles of Corrosion Engineering
Answer» Right choice is (B) 77 Easy explanation: We KNOW MDD = W/At = (Iam) / (dnF). We should convert the GIVEN UNIT values in milli inches per year. Given, I = 1.6910^-4 amp/cm^2 Atomic weight of iron = am = 55.86 g/mol n = number of electrons = 2 [Fe ==> Fe^+2 +2e^–] F = FARADAY’s constant = 96500 coulombs d=density of iron = 7.875 g/cm^3 = [(1.96×10^-4 coulombs/seccm^2) × (55.86)] ÷ [(7.874 g/cm^3×2×96500 coulombs)] = [(1.96×10^-4 coulombs/seccm^2) × (55.86)] ÷ [(7.874 g/cm^2cm×2×96500 coulombs)] = [(1.96×10^-4 1/sec) × (55.86)] ÷ [(7.874 g/cm ×2×96500)] = [1.69×10^-4 × (606024365) × (55.86) × 10^3] / [2 × 96500 × 7.875 × 2.54] = 77.117 MPY.

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