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Is in seconds. Find the impulse impartod to uN puuA ball of mass 100 g moving with a speed of 4 m/sec strikes a horizontal surface at an anglo of30° from the surface. The ball is reflected back with same speed and same angle of reflection find (a)The impulse imparted to the ball (b) change in magnitude of momentum of the ballE-2.10cm in dameter fall with an average speed of 20 m/s. |
Answer» <p>let ball is moving in x-y plane & approaching a wall at an angle 30 degree which is placed in y-z plane...</p><p>initial momentam of ball is Pi=mvcos30 i + mvsin30(-j)</p><p>finally it returnes at same angle & with same velocity so its final momntam is</p><p>Pf= mvcos30(-i) + mvsin30(-j)</p><p>change in momentam= Pi- Pi=2mvcos30</p><p> =mv</p><p> =100v</p> | |