1.

Is it possible that the sum of any consecutive ten terms of the sequence is 500?Why?First term is 2Common difference is 4​

Answer»

Step-by-step EXPLANATION:

a=2

d=4

n=10

s^10=500

s^10=n/2 [2a+(n-1)d]

=10/2 [2(2)+9(4)]

=5 (4+36)

=5 (40)

=200

s^10=200

which is not EQUAL to 500



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