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Is it possible that the sum of any consecutive ten terms of the sequence is 500?Why?First term is 2Common difference is 4 |
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Answer» Step-by-step EXPLANATION: a=2 d=4 n=10 s^10=500 s^10=n/2 [2a+(n-1)d] =10/2 [2(2)+9(4)] =5 (4+36) =5 (40) =200 s^10=200 which is not EQUAL to 500 |
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