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Is it possible to have a Binomial distribution with mean 5 and standarddeviation 3. Verify your answer mathematically​

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SOLUTION

TO VERIFY

Is it possible to have a Binomial distribution with mean 5 and standard deviation 3

EVALUATION

Let for the given Binomial distribution two parameters are N , p

Then

Mean = np

\sf{Standard  \: Deviation =  \sqrt{npq}  }

Now it is given that the Binomial distribution is with mean 5 and standard deviation 3

So by the given CONDITION

\sf{np = 5 \:  \:  \:  -  -  - (1)}

\sf{ \sqrt{npq} = 3 }

\sf{ \implies \:  {npq} = 9 }

\sf{ \implies \: 5q= 9 }

\displaystyle \sf{ \implies \: q=  \frac{9}{5}  }

\displaystyle \sf{ \implies \: 1 - p=  \frac{9}{5}  }

\displaystyle \sf{ \implies \: p=   - \frac{4}{5}  }

Which is absurd as probability of an event can not be negative ( 0 ≤ p ≤ 1 )

Hence such Binomial distribution is not possible

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