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Is kelvin circulation does not require the dyed circuit?(a) True(b) FalseI had been asked this question in exam.This question is from Kelvin’s Circulation Theorem and the Starting Vortex in chapter Incompressible Flow over Airfoils of Aerodynamics

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The correct ANSWER is (a) True

To explain: The kelvin circulation theorem does not require the FLUID region to be simply connected, it does not require the dyed circuit C to be placed by a SURFACE Slying wholly in the fluid, this CONDITION is only applied to the vortex shedding off an airfoil.



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