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Is photoelectric emission possible at all frequencies ? Give reason for your answer . |
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Answer» SOLUTION :Kinetic energy of photoelectrons is GIVEN by Einstein.s PHOTOELECTRIC equation `K_max = 1/2 mv_max^2 = hv - omega_0` = `(hv)/lembda - omega_0` `therefore v_max^2 prop 1/lambda` `v_max prop 1/sqrtlembda`. As the wavelength of incident LIGHT decreases, the velocity of photoelectrons increases. |
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