1.

Is there any value of k for which the equation x²+2x+(k²+1) = 0 has real roots​

Answer»

x²+2x+(k²+1)=0a=1 b=2 c=k²+1d=b²-4ac=0 2²-4×1×(k²+1)=0 4-4k²+4=0 8-4k²=0 4(2-k²)=0 2-k²=0 -k²=-2 k²=2 k=√2



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