1.

Iso-propylamine caimot be obtained by

Answer»




Solution :`(a) (CH_(3))_(2)CO+NH_(2)OHunderset(-H_(2)O)(rarr)(CH_(3))_(2)C=NOH overset("LiAIH"_(4))(rarr)(CH_(3))_(2)CHNH_(2)`
(B) `(CH_(3))_(2)COoverset(NH_(3).Delta)underset(-H_(2)O)(rarr)(CH_(3))_(2)C=NHoverset(H_(2)//Ni)underset((CH_(3))_(2)CHNH_(2))(rarr)`
(c ) `(CH_(3))_(2)CH-Broverset(NaNH_(2))underset(-HBr)(rarr)CH_(3)-CH=CH_(2)`
`(CH_(3))_(2)CHOH+NH_(3)overset(Al_(2)O_(3),633K)underset(-H_(2)O)(rarr)(CH_(3))_(2)CHNH_(2)`
Since `NH_(2)^(-)` is a strong base it prefers to abstract a proton to fonn an alkene RATHER than BRINGING about substitution reaction. Therefore, reaction ( c) cannot give iso-propylamine.


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