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it can take 12 hours to fill a swimming pool using 2 pipes .if the pipes of larger diameter is used for 4 hours and smaller diameter for 9 hours ,only half of the pool can be filled .how long will it take for each pipe to fill the pool separately |
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Answer» let the time taken by the first PIPE be x HOURS and the time taken by the SECOND pipe be y hours. in 1 hour the first pipe can fill it = 1/x in 1 hour the second pipe can fill it = 1/y 1/x +1/y = 1/12 --------------(1) 4/x = 9/9 =1/2---------------(2) Consider 1/x be a and 1/y be b. a + b = 1/12 -------------(3) 4A + 9b = 1/2 ----------------(4) multiply 3 by equ (4) and then subtract equ(5) from equ(4). 4a + 4B =1/3 --------------(5) we get, b = 1/30 y = 30. sustituting the value of y in equ(3) we get a + 1/30 = 1/12 x = 20. Hence the first pipe would take 20 hours and the second pipe would take 30 hours |
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