

InterviewSolution
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It is a rational number because it is a repeating decimal.(a) \(\frac{124}{165}\) (b) \(\frac{131}{30}\) (c) \(\frac{2027}{625}\)(d) \(\frac{1625}{462}\) |
Answer» (c) \(\frac{2027}{625}\) \(\frac{124}{165}\) = \(\frac{124}{5\times33'}\). we know 5 and 33 are not the factors of 124. It is in its simplest form and it cannot be expressed as the product of (2m × 5n) for some non-negative integers m, n. So, it cannot be expressed as a terminating decimal. \(\frac{131}{30}\) = \(\frac{131}{5\times6'}\). we know 5 and 6 are not the factors of 131. It is in its simplest form and it cannot be expressed as the product of (2m × 5n) for some non-negative integers m, n. So, it cannot be expressed as a terminating decimal. \(\frac{2027}{625}\) = \(\frac{2027\times2^4}{5^4\times2^4}\) = \(\frac{32432}{10000}\) = 3.2432; as it is of the form (2m × 5n), where m, n are non-negative integers. So, it is a terminating decimal \(\frac{1625}{462}\) = \(\frac{1625}{2\times7\times33'}\). we know 2, 7 and 33 are not the factors of 1625. It is in its simplest form and it cannot be expressed as the product of (2m × 5n) for some non-negative integers m, n. So, it cannot be expressed as a terminating decimal. |
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