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It Is Being Given That (232 + 1) Is Completely Divisible By A Whole Number. Which Of The Following Numbers Is Completely Divisible By This Number ? |
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Answer» Let 232 = x. Then, (232 + 1) = (x + 1). Let (x + 1) be completely DIVISIBLE by the natural number N. Then, (296 + 1) = [(232)3 + 1] = (x3 + 1) = (x + 1)(X2 - x + 1), which is completely divisible by N, since (x + 1) is divisible by N. Let 232 = x. Then, (232 + 1) = (x + 1). Let (x + 1) be completely divisible by the natural number N. Then, (296 + 1) = [(232)3 + 1] = (x3 + 1) = (x + 1)(x2 - x + 1), which is completely divisible by N, since (x + 1) is divisible by N. |
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