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It is practically difficult to calculate the equivalent conductivity of a weak electrolyte in aqueous solution. Comment. |
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Answer» Solution :Equivalent conductance = `(k xx 1000)//"normality"`. The extent of dissociation of a weak is less. According the number of IONS FURNISHED in AQUEOUS solutions is less. The specific conductivity (k) of a weak electrolyte is in the order of `10^(-2) S m^(-1)` or less. Since k is less, it is difficult to calculate equivalent conductivity of a weak electrolyte. |
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