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| 1. |
It os practically difficult to calculate the equivalent conductivity of a weak electrolyte in aqueous solutions. Comment. |
| Answer» Solution :Equivalent CONDUCTANCE ` = (k xx 1000) `/ normality. The extent of DISSOCIATION of a wea ELECTROLYTE is less. Accordingly the number of ions furnished in aqueous solution is less. The specific CONDUCTIVITY (k) of a weak electrolyte is in the order `10^(-2)S m^(-1)` of or less. Sincek is less, it is difficult to calculate equivalent conductivity of a weak electrolyte. | |