1.

It was found that for a reaction, on changin the temperature the t_(1//2) value get decreased. Hence it can be said that

Answer»

`T_(2)gtT_(1)` Reaction is exothermic
`T_(2)gtT_(1)` Reaction is endothermic
`T_(2)gtT_(1)` Reaction may be endothermic or exothermic
None of these

Solution :(I) Endo : A+Energy `to` PRODUCT `r_(f)=K_(f)[A]^(1),(t_(1/2))=[0.693/(K_(f))]` if tem `uarr` then `r_(f)uarr, K_(f)uarr,(t_(1/2))darr`
(II) Exop `ATO` Product + Energy , `r_(f)=K_(f)[A]^(1)(t_(1/2))=(0.693/(K_(f)))` If `Tuarr,r_(f)darr,K_(f)darr,(t_(1/2))uarr`
(III) But for both Exo & Endo themr if `Tuarr` then `K_(f)uarr` & `(t_(1/2))darr`


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