(iv) An elevator descends into a mine shaft at the rate of 8 m/min. If – InterviewSolution

1.	(iv) An elevator descends into a mine shaft at the rate of 8 m/min. If the descent starts from 20 m above ground level, how long will it take to reach - 460
Answer» 60 MINUTES or 1 hourStep-by-step explanation: level above GROUND = 20m level below the ground = - 460mTherefore the total distance= (20-(-460)) m = (460 + 20) m =480 m Speed = 8m/MIN.We know that time = distance/ speed = (480/8) min =60 min or 1 hour

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