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J. find the probality of getting 1. at least I head2. at Jeast I Tail3. two head4.Three tail5.Two head and one tail6. at most 3 tail When 3 coins are tossed |
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Answer» 1. 7/82.7/83.3/84.1/85.3/86.7/8Step-by-step explanation:S={HHH, HHT, HTH, THH, TTT, TTH, THT, HTT}n(S) = 8Event AA ={HHH, HHT, HTH, THH, TTH,THT,HTT}n(A) = 7P(A) = n(A)/n(S) = 7/8Event BB = {HHT, HTH, THH, TTT, TTH, THT, HTT}n(B) = 7P(B) = n(B)/n(S) = 7/8Event CC = {HHT, HTH, THH} n(C) = 3P(C) = n(C)/n(S) = 3/8Event DD = {TTT}n(D) = 1P(D) = n(D)/n(S) = 1/8Event EE = {HHT,HTH, THH}n(E) = 3P(E) = n(E)/n(S) = 3/8Event FF = {HHT, HTH, THH, TTT, TTH, THT, HTT}P(F) = n(F)/n(S) = 7/8 |
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