Saved Bookmarks
| 1. |
Jim throws a normal dice five times. Find out the probability that he throws no 3s |
|
Answer» Number of possible outcomes of a normal dice in 1ST throw = 6Therefore, the TOTAL number of possible outcomes after five times of throwing a normal dice = 6×5 =30Number of FAVOURABLE outcomes = 1Therefore, the total number of favourable outcomes after five times of throwing a normal dice = 1×6 = 6Hence, Probability = Total no. of favourable outcomes Total no. of possible outcomes =6/30 =1/5Therefore, the probability of getting a 3 after five times of throwing a normal dice is 1/5 |
|