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Answer»

Answer:

SOLUTION:-

f:N→Y

f(x)=4x2+12x+15

A function is INVERTIBLE if the function is one-one and onto.

Let X1,X2∈N, such that

f(x1)=f(x2)

4x12+12x1+15=4x22+12x2+15

⇒(x12−x22)+3(x1−x2)=0

⇒(x1−x2)(x1+x2+3)=0

∵x1,x2∈N

⇒x1+x2+3



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