Jones covered a distance of 50 miles on his first trip. On a later tri

1.	Jones covered a distance of 50 miles on his first trip. On a later trip he traveled 300 miles while going three times as fast. His new time compared with the old time was:(a) three times as much, (b) twice as much, (c) the same, (d) half as much, (e) a third as much
Answer» ⠀⠀ıllıllı uoᴉʇnloS ıllıllı $\setlength{\unitlength}{1.0 cm}}\begin{picture}(12,4)\thicklines\put(1,1){\line(1,0){6.5}}\put(1,1.1){\line(1,0){6.5}}\end{picture}$ Let SPEED of the 1st TRIP X miles / hr. and speed of the 2nd trip 3x / hr. We know that Speed = Distance/Time. Or, Time = Distance/Speed. So, times taken to covered a distance of 50 miles on his first trip = 50/x hr. And times taken to covered a distance of 300 miles on his later trip = 300/3x hr. = 100/x hr. So we can clearly see that his new time compared with the old time was: Twice as much. Hence, the OPTION B is CORRECT. $\setlength{\unitlength}{1.0 cm}}\begin{picture}(12,4)\thicklines\put(1,1){\line(1,0){6.5}}\put(1,1.1){\line(1,0){6.5}}\end{picture}$

Jones covered a distance of 50 miles on his first trip. On a later trip he traveled 300 miles while going three times as fast. His new time compared with the old time was:(a) three times as much, (b) twice as much, (c) the same, (d) half as much, (e) a third as much

Answer»

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Let SPEED of the 1st TRIP X miles / hr. and speed of the 2nd trip 3x / hr.

We know that

So, times taken to covered a distance of 50 miles on his first trip = 50/x hr.

And times taken to covered a distance of 300 miles on his later trip = 300/3x hr.

= 100/x hr.

So we can clearly see that his new time compared with the old time was: Twice as much.

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