1.

k_(2)CO_(3) cannot be prepared by solvay process because

Answer»

`KHCO_3` is less soluble than `NaHCO_3`
`KHCO_3` is too soluble to GET SEPARATED from solution
`K_2 O_3` is too soluble to be precipitated by KCL
`K_2CO_3` is less soluble than `Na_2CO_3`

ANSWER :B


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