k_(2)CO_(3) cannot be prepared by solvay process because
Answer»
`KHCO_3` is less soluble than `NaHCO_3` `KHCO_3` is too soluble to GETSEPARATED from solution `K_2 O_3` is too soluble to be precipitated by KCL `K_2CO_3` is less soluble than `Na_2CO_3`