1.

K_(2)HgI_(4) is 50% ionised in aqueous solution. Which of following are correct ?

Answer»

n = 7
n = 3
i = 2
i = 4

Solution :EXPLANATION : `K_(2)HgI_(4)RARR 2K^(+)+HgI_(4)^(2-)rArr n=3`
`alpha=(i-1)/(n-1),0.5=(i-1)/(3-1)rArr i=2`
`therefore` (b) and (c ) are correct while (a) and (d) are not correct.


Discussion

No Comment Found