1.

K_4 [Fe(CN)_6] can be used to detect one or more out of Fe^(2+), Fe^(3+), Zn^(2+), Cu^(2+), Cd^(2+)

Answer»

`Fe^(2+),Fe^(3+)`
`Fe^(3+),Zn^(2+),CU^(2+)`
All but `Fe^(3+)`
All but `Fe^(2+)`

Solution :`2ZnCl_(2) +K_(4)[Fe(CN)_(6)] overset(CH_(3)CO OH)to UNDERSET("(Prussian blue)")underset("Ferric ferrocyanide")(Fe_(4)[Fe(CN)_(6)]_(3)+12KCl`
`2Cu(NO_(3))_(2) + K_(4)[Fe(CN)_(6)] to underset("(Reddish brown)")(Cu_(2)[Fe(CN)_(6)])+4KNO_(3)`
`2CD(NO_(3))_(2)+K_(4)[Fe(CN)_(6)] to underset("(BLUISH white)")(Cd_(2)[Fe(CN)_(6)])+4KNO_(3)`


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