1.

K_4[Fe(CN)_6] can be used to detect one or more out of Fe^(2+),Fe^(3+),Zn^(2+),Ca^(2+):

Answer»

`Fe^(2+),Fe^(3+)` only
`Fe^(3+), Zn^(2+), Cu^(2+)` only
All but not `Ca^(2+)`
All

Solution :`Fe^(2+)+2K^(+)[Fe(CN)_6]darr` (white) (in absence of air)
`Fe^(3+)+[Fe(CN)_6]^(4-)toFe_4[Fe(CN)_6]_3`(PRUSSIAN blue PRECIPITATE or solution)
`Zn^(2+)+2K^(+)[Fe(CN)_6]^(4-)`(excess)`toK_2Zn_3[Fe(CN)_6]_2darr`(bluish -white/white)
`Ca^(2+)+2K^(+)[Fe(CN)_6]^(4-)toK_2Ca[Fe(CN)_6]darr`(white)
`Cu^(+)+2K^(+)+[Fe(CN)_6]^(4-)toCu_2[Fe(CN)_6]darr` [CHOCOLATE brown]


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