1.

K_(a) for butyric acid is 2.0 xx 10^(-5). Calculate pH and hydroxyl ion concentration in 0.2 M aqueous in 0.2 M aqueous solution of sodium butyrate

Answer»


Solution : `{:(,NaBu+,H_(2)O hArr,NaOH+,BUH),("Conc. before HYDROLYSIS",1,,0,0),("Conc. after hydrolysis",1-h,,h,h):}`
`:. [OH^(-)] = C.hCsqrt((K_(h))/(C)) = sqrt(K_(h).C) = sqrt((K_(w).C)/(K_(a)))`
`[OH^(-)] = (10^(-14) xx 0.2)/(2 xx 10^(-5)) = sqrt(10^(-10)) = 10^(-5)`
`:. pOH = -log[OH^(-)] = 5` and so pH = 14 - 5 = 9


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