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K_b and K_f for water are respectively 0.52 and 1.80 kg "mol"^(-1)respectively. For an aqueous glycolic solution freezing point is 3.72^@ C. What is the boiling point of the solution ? |
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Answer» Solution :DEPRESSION of freezing point =`Delta t_f =3.72^@C` `DeltaT_f = K_f XX m` , MOLALITY `m=DeltaT_f //K_f` =3.72/1.86 =2 mol `kg^(-1)` ELEVATION of BOILING point =`DeltaT_b=K_b xx m` `=0.52xx2=1.04^@C` Boiling point of the solution =100+1.04 =`101.04^@C` |
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