K_b for NH_4OH is 1.8 times 10^-5. Calculate the percentage of ionisat – InterviewSolution

1.	K_b for NH_4OH is 1.8 times 10^-5. Calculate the percentage of ionisation of 0.06 M ammonium hydroxide solution.
Answer» Solution :`a=SQRT(K_b/C)=sqrt((1 .8 times10^-5)/(6 times10^-2))=sqrt(3 times10^-4)=1.732 times10^-2=1.732 times10^-2 times100=1.732%`

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