1.

K_(e ) for the reaction N_(2)(g)+O_(2) hArr 2NO(g) at 300 K is 4.0xx10^(-6). K_(p) for the above reaction will be (R=2 " cal mol"^(-1)K^(-1))

Answer»

`2.4xx10^(-3)`
`4xx10^(-6)`
`4xx10^(-6) (RT)^(2)`
`16xx10^(-12)`

Solution :`K_(p)=K_(E )(RT)^(Delta N) " since " Delta n=0, K_(p)=K_(e )`


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