1.

K.E. of free electron doubles, its de-broglie wavelength changes by a factor :

Answer»

`(1)/(sqrt(2))`
`sqrt2`
`(1)/(2)`
2

Solution :`lambda=(12.27)/(sqrt(2mE)) RARR lambda prop (1)/(sqrt(E))`
`lambda. prop (1)/( sqrt(2E))`
`:. (lambda.)/(lambda)=(1)/(sqrt(2)) rArr lambda.=(lambda)/(sqrt(2))`


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