1.

K_(p) and K'_(p) are the equilibrium constants of the two reactions, given below 1/2N_(2(g))+3/2H_(2(g))hArrNH_(2(g))N_(2(g))+3H_(2(g))hArr2NH_(3(g)) Therefore, K_(p) and K'_(p) are related by

Answer»

`K_(p)=K_(p)^(2)`
`K_(2)sqrt(K'_(p))`
`K_(p)=2K'_(p)`
`K_(p)=K'_(p)`

Solution :When a balanced equation having equlibrium constant `K_(p)` is MULTIPLIED by a certain VALUE n, the equlibrium constant for the new equation will be equal to `(K_(p))^(n).` In the GIVEN equation, `n=2`
So, `K'_(p)=(K_(p))^(2)orK_(p)=sqrt(K'_(p))`


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