

InterviewSolution
Saved Bookmarks
1. |
`K_(p)` for `3//2H_(2)+1//2N_(2) hArr NH_(3)` are `0.0266` and `0.0129 atm^(-1)`, respectively, at `350^(@)C` and `400^(@)C`. Calculate the heat of formation of `NH_(3)`. |
Answer» Correct Answer - A::B::C::D `2.303 "log"K_(p_(2))/K_(p_(1))=(DeltaH)/(R)[(T_(2)-T_(1))/(T_(1)T_(2))]` `2.303"log"0.0129/0.0266=(DeltaH)/(2)[(673-623)/(673xx623)]` `:. DeltaH=12140 cal=-12140 cal` |
|