1.

K_(sp) for Cr(OH)_3 is 2.7 times 10^-3. What is the solubility in moles/litre?

Answer»

`1 TIMES 10^-8`
`8 times 10^-8`
`1.1 times 10^-8`
`0.18 times 10^-8`

Solution :`Cr(OH)_3 to Cr^(3+)+3OH^-`
x 3x
`K_(SP)=x.(3x)^3=27x^4`
`therefore x=4sqrt(K_(sp)/27)=4sqrt((2.7 times 10^-31)/27)`
`therefore x=1 times 10^-8`


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